Import Question JSON

Current Question (ID: 17935)

Question:

$\text{The anions (A) form hexagonal closest packing and atoms (C) occupy only } \frac{2}{3} \text{ of octahedral voids in it. The general formula of the compound is-}$

Options:

1. $\text{CA}$
2. $\text{CA}_2$
3. $\text{C}_2\text{A}_3$
4. $\text{C}_3\text{A}_2$

Solution:

$\text{Number of octahedral voids = Number of atoms present in hcp unit cell.}$ $\text{Hexagonal close-packing contains 6 atoms per unit cell and hence the number of octahedral voids per the unit cell is 6.}$ $\text{Hence, number of A atoms per unit cell = 6 and number of C atoms per unit cell = 6} \times \frac{2}{3} = 4$ $\text{The formula of an ionic compound is given as the simplest formula and hence formula is } \text{C}_2\text{A}_3$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}