Import Question JSON

$\text{Hint: This question gives the knowledge about the FCC crystal lattice. FCC crystal lattice is called as face-centered cubic crystal lattice. It contains six atoms at each face of the cube and eight atoms at the corners of the cube.}$ $\text{Formula used: The formula used to determine the radius of the metal atom is as follows:}$ $r = \frac{a}{2\sqrt{2}}$ $\text{Where } r \text{ is the radius of the metal atom and } a \text{ is the edge length of the unit cell}$ $\text{FCC crystal lattice contains six atoms at each face of the cube and eight atoms at the corners of the cube. The effective number of atoms in a FCC crystal unit cell is always 4. The coordination number of FCC lattice is 12. The elements which possess face centered unit cells are copper, aluminium, silver and so forth. Face centered crystal lattice is a closed packed structure.}$ $\text{Now, we will determine the radius of the metal atom as follows:}$ $\Rightarrow r = \frac{a}{2\sqrt{2}}$ $\text{Substitute the value of the edge length of the unit cell as 408 pm in the above formula to determine the radius.}$ $\Rightarrow r = \frac{408}{2\sqrt{2}}$ $\text{On simplifying, we get}$ $\Rightarrow r = 144 \text{ pm}$ $\text{As we know, the diameter is the double of radius of the metal atom. So, the radius is multiplied by 2 to determine the diameter.}$ $\text{Therefore, the diameter of the metal atom is 288 pm.}$