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Current Question (ID: 17962)

Question:

$\text{Same coordination number for cations and anions is present in:}$

Options:

1. $\text{Cl}^- \text{ ions form Fcc lattice and Na}^+ \text{ ions occupy all octahedral voids of the unit cell.}$
2. $\text{Ca}^{2+} \text{ ions form Fcc lattice and F}^- \text{ ions occupy all the eight tetrahedral voids of the unit cell.}$
3. $\text{O}^{2-} \text{ ions form Fcc lattice and Na}^+ \text{ ions occupy all the eight tetrahedral voids of the unit cell.}$
4. $\text{S}^{2-} \text{ ions form Fcc lattice and K}^+ \text{ ions go into alternate tetrahedral voids of the unit cell.}$

Solution:

$\text{HINT: Octahedral void coordination number is 6}$ $\text{Explanation:}$ $\text{NaCl crystals have rock salt structures having Fcc lattice in which Cl}^- \text{ ions are present at Fcc lattice points and face center and Na}^+ \text{ occupies all the octahedral void of given unit cell.}$ $\text{Where, coordination number of Na}^+ = 6$ $\text{coordination number of Cl}^- = 6$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}