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Current Question (ID: 17965)

Question:

$\text{A cubic solid is made of two elements P and Q. Atoms of Q occupy the corners of the cube and P occupy the body centre. The formula of this compound and the coordination number of Q are respectively -}$

Options:

1. $\text{PQ, 8}$
2. $\text{P}_2\text{Q, 8}$
3. $\text{P}_2\text{Q}_2, 8}$
4. $\text{PQ, 12}$

Solution:

$\text{HINT: If an atom is present at the body-center, the coordination number will be 8.}$ $\text{STEP 1:}$ $\text{It is given that the atoms of Q are present at the corners of the cube.}$ $\text{Therefore, the number of atoms of Q in one unit cell=} 8 \times \frac{1}{8} = 1$ $\text{It is also given that the atom of P is present at the body-centre.}$ $\text{Therefore, number of atoms of P in one unit cell = 1}$ $\text{STEP 2:}$ $\text{This means that the ratio of the number of P atoms to the number of Q atoms, P : Q = 1:1}$ $\text{Hence, the formula of the compound is PQ.}$ $\text{The coordination number of Q is 8.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}