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Current Question (ID: 17966)

Question:

$\text{A ferric oxide crystallizes in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. The formula of the ferric oxide is-}$

Options:

1. $\text{FeO}$
2. $\text{Fe}_2\text{O}_3$
3. $\text{Fe}_3\text{O}_4$
4. $\text{Fe}_3\text{O}_2$

Solution:

$\text{Hint: Number of octahedral voids = number of oxide ions.}$ $\text{Let the number of oxides (O}^{2-}\text{) ions be } x. \text{ So, the number of octahedral voids } = x.$ $\text{It is given that two out of every three octahedral holes are occupied by ferric ions.}$ $\text{So, the number of ferric (Fe}^{3+}\text{) ions} = \frac{2}{3}x.$ $\text{The ratio of the number of Fe}^{3+}\text{ ions to the number of O}^{2-}\text{ ions,}$ $\text{Fe}^{3+} : \text{O}^{2-} = \frac{2}{3}x : x = \frac{2}{3} : 1 = 2 : 3.$ $\text{Hence, the formula of the ferric oxide is Fe}_2\text{O}_3.$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}