Import Question JSON

Current Question (ID: 17970)

Question:

$\text{Match the type of packing given in Column I with the items given in Column II.}$ $\begin{array}{|c|c|} \hline \text{Column I} & \text{Column II} \\ \hline \text{A. Square close packing in two dimensions} & \text{1. Triangular voids} \\ \text{B. Hexagonal close packing in two dimensions} & \text{2. Pattern of spheres is repeated in every fourth layer} \\ \text{C. Hexagonal close packing in three dimensions} & \text{3. Coordination number = 4} \\ \text{D. Cubic close packing in three dimensions} & \text{4. Pattern of sphere is repeated in alternate layers} \\ \hline \end{array}$

Options:

1. $\begin{array}{cccc} 3 & 2 & 4 & 1 \end{array}$
2. $\begin{array}{cccc} 1 & 2 & 3 & 4 \end{array}$
3. $\begin{array}{cccc} 3 & 1 & 4 & 2 \end{array}$
4. $\begin{array}{cccc} 4 & 1 & 3 & 2 \end{array}$

Solution:

$\text{Hint: Square close packing in two dimensions has coordination number 4.}$ $\text{A. Square close packing in two dimensions each sphere have coordination number 4, as shown below}$ $\text{B. Hexagonal close packing in two dimensions each sphere have coordination number 6 as shown below and creates a triangular void}$ $\text{C. Hexagonal close packing in 3 dimensions is a repeated pattern of sphere in alternate layers also known as } ABAB \text{ pattern}$ $\text{D. Cubic close packing in a 3 dimensions is a repeating pattern of sphere in every fourth layer}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}