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Current Question (ID: 17977)

Question:

$\text{A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75 \% of octahedral voids.}$ $\text{The formula of the compound is:}$

Options:

1. $\text{C}_3\text{A}_4$
2. $\text{C}_2\text{A}_3$
3. $\text{C}_3\text{A}_2$
4. $\text{C}_4\text{A}_3$

Solution:

$\text{HINT: Number of octahedral voids in hcp} = 6$ $\text{STEP 1:}$ $\text{Number of atom per unit cell in hcp} = 6$ $\text{number of octahedral void in hcp} = 6$ $\text{Number of anions per unit cell} = 6$ $\text{STEP 2:}$ $\text{Anions (A) are in hcp, so the number of anions (A)} = 6$ $\text{Cations (C) are in 75\% O.V so number of cations (C)} = 6 \times \frac{75}{100} = \frac{18}{4} = \frac{9}{2}$ $\text{So the formula of the compound will be: } \text{C}_9\text{A}_{12} = \text{C}_9\text{A}_{12} = \text{C}_3\text{A}_4$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}