Import Question JSON

Current Question (ID: 17990)

Question:

$\text{Match the defects given in Column I with the statements given in Column II.}$ $\begin{array}{|c|c|} \hline \text{Column I} & \text{Column II} \\ \hline \text{A. Simple vacancy defect} & \text{1. Shown by non-ionic solids and increases the density of the solid} \\ \text{B. Simple interstitial defect} & \text{2. Shown by ionic solids and decreases the density of the solid} \\ \text{C. Frenkel defect} & \text{3. Shown by non-ionic solids and decreases the density of the solid} \\ \text{D. Schottky defect} & \text{4. Shown by ionic solids and density of the solid remains the same} \\ \hline \end{array}$

Options:

1. $\begin{array}{cccc} 1 & 2 & 3 & 4 \\ \end{array}$
2. $\begin{array}{cccc} 1 & 4 & 3 & 2 \\ \end{array}$
3. $\begin{array}{cccc} 4 & 1 & 3 & 2 \\ \end{array}$
4. $\begin{array}{cccc} 4 & 3 & 1 & 2 \\ \end{array}$

Solution:

$\text{Hint: Frenkel Defect, shown by ionic solids. The smaller ion (usually cation) is dislocated from its normal site to an interstitial site.}$ $\text{A. When some of lattice sites are vacant in any non-ionic solid, the crystal is said to have vacancy defect and due to decrease in number of particles present in crystal lattice the density of crystal decreases.}$ $\text{B. Simple interstitial defect are shown by non-ionic solids in which constituent particles is displaced from its normal site to an interstitial site. Hence, density of solid increases.}$ $\text{C. Frenkel defect is shown by ionic solids in which smaller ions get dislocated from its normal site to its interstitial site which lead to decrease its density.}$ $\text{D. Schottky defect is shown by ionic solids in which equal number of cation and anion get missed from ionic solids and thus, density of solid decreases.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}