Import Question JSON

Current Question (ID: 17996)

Question:

$\text{Match the types of defects given in Column I with the statement given in Column II.}$ $\begin{array}{|c|c|} \hline \text{Column I} & \text{Column II} \\ \hline \text{A. Impurity defect} & \text{1. NaCl with anionic sites called F-centres} \\ \text{B. Metal excess defect} & \text{2. FeO with Fe}^{3+} \\ \text{C. Metal deficiency defect} & \text{3. NaCl with Sr}^{2+} \text{ and some cationic sites vacant} \\ \hline \end{array}$ $\text{Codes}$ $\begin{array}{|c|c|c|c|} \hline & \text{A} & \text{B} & \text{C} \\ \hline 1. & 2 & 3 & 1 \\ 2. & 3 & 1 & 2 \\ 3. & 1 & 2 & 3 \\ 4. & 2 & 1 & 3 \\ \hline \end{array}$

Options:

1. $2 \ 3 \ 1$
2. $3 \ 1 \ 2$
3. $1 \ 2 \ 3$
4. $2 \ 1 \ 3$

Solution:

$\text{Hint: Non-Stoichiometric Defects.}$ $\text{Explanation:}$ $\text{A. Impurity defect arises due to replacement of one common ion present in any crystal by another uncommon ion. In the case of NaCl, some of the sites of Na}^{+} \text{ ions are occupied by Sr}^{2+} \text{ ion.}$ $\text{B. Metal excess defect is due to missing of cation from ideal ionic solid which lead to create a F-centre generally occupied by unpaired electrons. e.g., NaCl with the anionic site.}$ $\text{C. Metal deficiency defect In FeO, Fe}^{3+} \text{ exists along with Fe}^{2+} \text{ which lead to a decrease in metal ion(s) so this is a type of metal deficiency defect.}$ $\text{Thus, option 2 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}