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Current Question (ID: 18006)

Question:
$\text{Consider the following statements about semiconductors.}$ $\text{I. Silicon doped with electron-rich impurity is a p-type semiconductor.}$ $\text{II. Silicon doped with an electron-rich impurity is an n-type semiconductor.}$ $\text{III. Delocalised electrons increase the conductivity of doped silicon.}$ $\text{IV. An electron vacancy increases the conductivity of n-type semiconductor.}$ $\text{The correct statements about semiconductors are:}$
Options:
  • 1. $\text{I and II}$
  • 2. $\text{II and III}$
  • 3. $\text{III and IV}$
  • 4. $\text{I and IV}$
Solution:
$\text{Silicon doped with an electron-rich impurity is an n-type semiconductor.}$ $\text{The conductivity of n-type semiconductors is due to the presence of delocalized electrons.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}