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Current Question (ID: 18009)

Question:
$\text{Which of the following arrangements shows the schematic alignment of magnetic moments of antiferromagnetic substances?}$
Options:
  • 1. $\uparrow \uparrow \uparrow \uparrow \uparrow \uparrow$
  • 2. $\downarrow \downarrow \downarrow \downarrow \downarrow \downarrow$
  • 3. $\uparrow \uparrow \downarrow \downarrow \uparrow \uparrow$
  • 4. $\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow$
Solution:
$\text{HINT: Domains are oppositely oriented and cancel out each other's magnetic moment.}$ $\text{Explanation:}$ $\text{The substances which have domain structure are oppositely oriented and cancel each other's magnetic field are known as antiferromagnetic substances.}$ $\text{The antiferromagnetic materials are commonly found among the transition metal compounds.}$ $\text{Hematite, chromium, alloys of iron manganese and oxides of nickel are the examples of antiferromagnetic material.}$ $\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow$ $\text{Schematic arrangement of antiferromagnetic substance}$ $\text{Thus, option 4 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}