Import Question JSON

Current Question (ID: 18016)

Question:
$\text{The correct match for the below table is:}$ $\begin{array}{|c|c|} \hline \text{Type of solution} & \text{Example} \\ \hline \text{a. Solid in gas} & \text{i. Aerated water} \\ \text{b. Gas in liquid} & \text{ii. Smoke} \\ \text{c. Liquid in solid} & \text{iii. Solution of hydrogen in palladium} \\ \text{d. Gas in solid} & \text{iv. Amalgams} \\ \hline \end{array}$ $\begin{array}{cccc} \text{a} & \text{b} & \text{c} & \text{d} \\ 1. & \text{i} & \text{iii} & \text{iv} & \text{ii} \\ 2. & \text{ii} & \text{i} & \text{iv} & \text{iii} \\ 3. & \text{iii} & \text{i} & \text{iv} & \text{ii} \\ 4. & \text{iv} & \text{i} & \text{ii} & \text{iii} \end{array}$
Options:
  • 1. $\text{i, iii, iv, ii}$
  • 2. $\text{ii, i, iv, iii}$
  • 3. $\text{iii, i, iv, ii}$
  • 4. $\text{iv, i, ii, iii}$
Solution:
$\text{Hint: A Solution is a homogeneous mixture of two or more chemically non-reacting substances.}$ $\text{Types of Solution Examples}$ $\text{Gaseous solutions:}$ $\text{(a) Gas in gas: Air, mixture of } \text{O}_2 , \text{N}_2 \text{O}_2 \text{ and } \text{N}_2 , \text{ etc.}$ $\text{(b) Liquid in gas: Water vapor}$ $\text{(c) Solid in gas: Camphor vapours in } \text{N}_2 \text{ gas, smoke, etc.}$ $\text{Liquid solutions}$ $\text{(a) Gas in liquid: } \text{CO}_2 \text{ dissolved in water (aerated water), and } \text{O}_2 \text{ dissolved in water, etc.}$ $\text{(b) Liquid in liquid: Ethanol dissolved in water, etc.}$ $\text{(c) Solid in liquid: Sugar dissolved in water, saline water, etc.}$ $\text{Solid Solutions}$ $\text{(a) Gas in solid: Solution of hydrogen in palladium}$ $\text{(b) Liquid in solid: Amalgams, e.g. Na-Hg.}$ $\text{(c) Solid in solid: Gold ornaments (Cu/Ag with Au).}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}