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Current Question (ID: 18020)

Question:
$\text{An aqueous solution of hydrochloric acid -}$ $1. \text{ Obeys Raoult's law}$ $2. \text{ Shows negative deviations from Raoult's law}$ $3. \text{ Shows positive deviations from Raoult's law}$ $4. \text{ Obeys Henry's law at all compositions}$
Options:
  • 1. $\text{Obeys Raoult's law}$
  • 2. $\text{Shows negative deviations from Raoult's law}$
  • 3. $\text{Shows positive deviations from Raoult's law}$
  • 4. $\text{Obeys Henry's law at all compositions}$
Solution:
$\text{Hint: Molecule undergoes dissociation or association did not follow Raoult's law.}$ $\text{If the attraction between different molecules, for example between HCl and H}_2\text{O molecules, is stronger, then the escaping tendency of solute or solvent}$ $\text{from the solution to the vapor phase will be smaller. As a result, the partial}$ $\text{vapor pressure will be smaller than predicted by Raoult's law and the system}$ $\text{exhibits a negative deviation.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}