Import Question JSON

Current Question (ID: 18025)

Question:

$\text{Match the items given in Column I with the type of solutions given in Column II.}$ $\begin{array}{|c|c|} \hline \text{Column I} & \text{Column II} \\ \hline \text{A. Soda water} & \text{1. A solution of gas in solid} \\ \text{B. Sugar solution} & \text{2. A solution of gas in liquid} \\ \text{C. German silver} & \text{3. A solution of solid in liquid} \\ \text{D. Hydrogen gas in palladium} & \text{4. A solution of solid in solid} \\ \hline \end{array}$ $\text{Codes:}$ $\begin{array}{cccc} & \text{A} & \text{B} & \text{C} & \text{D} \\ 1. & 2 & 1 & 4 & 3 \\ 2. & 1 & 2 & 3 & 4 \\ 3. & 2 & 3 & 4 & 1 \\ 4. & 4 & 1 & 3 & 2 \\ \end{array}$

Options:

1. $2 \ 1 \ 4 \ 3$
2. $1 \ 2 \ 3 \ 4$
3. $2 \ 3 \ 4 \ 1$
4. $4 \ 1 \ 3 \ 2$

Solution:

$\text{Hint: A solution of gas in liquid. e.g., } \text{CO}_2 \text{ in soft drinks.}$ $\text{Explanation:}$ $\text{A. Soda water: A solution of gas in liquid. e.g., } \text{CO}_2 \text{ in soft drinks.}$ $\text{B. Sugar solution: A solution of solid in liquid in which sugar particles (solid) are dissolved in water (liquid).}$ $\text{C. German silver: Is an alloy in which is a solid solution of solid in solid. It is an alloy of Cu, Zn and Ni.}$ $\text{D. Hydrogen gas in palladium is an example of solution of gas in solid. This is used as an reducing agent.}$ $\text{Thus, option 3 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}