Import Question JSON

Current Question (ID: 18030)

Question:

$\text{The incorrect formula among the following is:}$ $1. \text{X}_{\text{mole fraction}} = \frac{n_{\text{solute}}}{n_{\text{solution}}}$ $2. \text{Molarity} = \frac{\text{amount of solute (g)}}{\text{volume of solution (mL)}}$ $3. \text{Molality} = \frac{\text{Number of mole of solute}}{\text{amount of solvent (kg)}}$ $4. \text{Mass percentage} = \frac{\text{mass of the component in the solution}}{\text{Total mass of the solution}} \times 100$

Options:

1. $\text{X}_{\text{mole fraction}} = \frac{n_{\text{solute}}}{n_{\text{solution}}}$
2. $\text{Molarity} = \frac{\text{amount of solute (g)}}{\text{volume of solution (mL)}}$
3. $\text{Molality} = \frac{\text{Number of mole of solute}}{\text{amount of solvent (kg)}}$
4. $\text{Mass percentage} = \frac{\text{mass of the component in the solution}}{\text{Total mass of the solution}} \times 100$

Solution:

$\text{Hint: Molarity unit is mol L}^{-1}$ $\text{Explanation:}$ $\text{The formula of mole fraction, molality, and mass percentage is correct.}$ $\text{The correct formula of molarity is as follows:}$ $\text{Molarity} = \frac{\text{Number of mole of solute}}{\text{volume of solution (L)}}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}