Import Question JSON

Current Question (ID: 18047)

Question:

$4 \text{ L of } 0.02 \text{ M aqueous solution of } \text{NaCl} \text{ was diluted by adding } 1 \text{ L of water. The molarity of the resultant solution is:}$

Options:

1. $0.004 \text{ M}$
2. $0.008 \text{ M}$
3. $0.012 \text{ M}$
4. $0.016 \text{ M}$

Solution:

$\text{Hint: } M_1 V_1 = M_2 V_2$ $\text{Step 1:}$ $\text{Given, } M_1 = 0.02\text{M, } V_1 = 4\text{L, } M_2 = ?, V_2 = 4\text{L} + 1\text{L} = 5\text{L}$ $\text{Step 2:}$ $\text{As we know, } M_1 V_1 = M_2 V_2$ $0.02 \times 4\text{L} = M_2 \times 5\text{L}$ $M_2 = \frac{0.08}{5} = 0.016 \text{ M}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}