Import Question JSON

Current Question (ID: 18050)

Question:

$\text{A solution is obtained by mixing } 300 \text{ g of } 25 \% \text{ solution and } 400 \text{ g of } 40 \% \text{ solution by mass. The mass percentage of solute in the resulting solution is:}$

Options:

1. $33.5 \%$
2. $36.5 \%$
3. $37.4 \%$
4. $32.5 \%$

Solution:

$\text{Hint: Mass percentage} = \frac{\text{mass of the component in the solution}}{\text{Total mass of the solution}} \times 100$ $\text{Step 1:}$ $\text{Find the total amount of solute in a resulting solution}$ $\text{The amount of } 300 \text{ g of } 25\% \text{ solution} = 300 \times \frac{25}{100} = 75 \text{ g}$ $\text{The amount of } 400 \text{ g of } 40\% \text{ solution} = 400 \times \frac{40}{100} = 160 \text{ g}$ $\text{Total amount of solute} = 75 \text{ g} + 160 \text{ g} = 235 \text{ g}$ $\text{Step 2:}$ $\text{Calculate the mass percent of solute in the resulting solution is as follows:}$ $\text{Mass percentage} = \frac{\text{mass of solute}}{\text{Total mass of the resulting solution}} \times 100$ $\text{Mass percentage} = \frac{235}{700} \times 100$ $\text{Mass percentage} = 33.5 \%$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}