Import Question JSON

Current Question (ID: 18057)

Question:

$\text{Select the correct option based on statements below:}$ $\text{Assertion (A): } \text{C}_2\text{H}_5\text{I and C}_2\text{H}_5\text{Br form an ideal solution.}$ $\text{Reason (R): } \text{The interaction between the components are similar to those in the pure components.}$

Options:

1. $\text{Both (A) and (R) are true and (R) is the correct explanation of (A).}$
2. $\text{Both (A) and (R) are true but (R) is not the correct explanation of (A).}$
3. $\text{(A) is true but (R) is false.}$
4. $\text{Both (A) and (R) are false.}$

Solution:

$\text{Hint: In an Ideal solution, solute-solute and solvent-solvent are equal to solute-solvent interaction.}$ $\text{In an alkyl halide, the carbon-halogen bonds (apart from the carbon-iodine bond) are polar, because the electron pair is pulled closer to the halogen atom than the carbon. Thus, they show dipole-dipole interaction.}$ $\text{In the case of } \text{C}_2\text{H}_5\text{I and C}_2\text{H}_5\text{Br, the interaction between C}_2\text{H}_5\text{I molecules and C}_2\text{H}_5\text{Br molecules is equal to the interaction between C}_2\text{H}_5\text{I and C}_2\text{H}_5\text{Br molecules.}$ $\text{Hence, both Assertion and Reason are true and the reason is the correct explanation of the assertion.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}