Import Question JSON

Current Question (ID: 18076)

Question:

$\text{The Vapour pressure of CCl}_4 \text{ at } 25^\circ\text{C is } 143 \text{ mm Hg. } 0.5 \text{ g of a non-volatile solute (mol. wt. 65) is dissolved in } 100 \text{ ml of CCl}_4. \text{ The vapor pressure of the solution is-}$ $\text{(Density of CCl}_4 = 1.58 \text{ g/cm}^3)}$

Options:

1. $141.93 \text{ mm Hg}$
2. $94.39 \text{ mm Hg}$
3. $199.34 \text{ mm Hg}$
4. $143.99 \text{ mm Hg}$

Solution:

$\text{Hint: } \frac{P^o - P_s}{P^o} = \frac{n_2}{n_1}$ $\text{Step 1:}$ $\text{By using the relative lowering of vapour pressure equation.}$ $\frac{P^o - P_s}{P^o} = \frac{n_2}{n_1}$ $\frac{143 - P_s}{143} = \frac{0.5/65}{158/154}$ $\frac{143 - P_s}{143} = 0.0076$ $\frac{143 - P_s}{143} = 0.0074$ $\text{Step 2:}$ $143 - P_s = 0.0074 \times 143 = 1.06$ $P_s = 143 - 1.06$ $= 141.93 \text{ mm Hg}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}