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Current Question (ID: 18078)

Question:

$\text{An aqueous solution is 1.00 molal in KI. The vapour pressure of the solution can be increased by:}$ $1. \text{ Addition of NaCl}$ $2. \text{ Addition of Na}_2\text{SO}_4$ $3. \text{ Addition of 1.00 molal KI}$ $4. \text{ Addition of water}$

Options:

1. $\text{Addition of NaCl}$
2. $\text{Addition of Na}_2\text{SO}_4$
3. $\text{Addition of 1.00 molal KI}$
4. $\text{Addition of water}$

Solution:

$\text{Hint: Vapour pressure is surface phenomena}$ $\text{The vapour pressure is directly proportional to the surface area of the solution.}$ $\text{When a solute is added, the vapour pressure is decreased because the solute particles occupy some of the sites of the surface area.}$ $\text{This results in the reduction of the surface area.}$ $\text{But on dilution, when the solvent is added, the surface area of the liquid surface is increased and the vapour pressure increases.}$ $\text{Hence when water is added to the aqueous solution of KI, the vapour pressure is increased.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}