Import Question JSON

Current Question (ID: 18085)

Question:
$\text{The mole(s) of } \text{K}_2\text{SO}_4 \text{ to be dissolved in 12 moles of water to lower its vapor pressure by 10 mm of Hg at a temperature at which vapor pressure of pure water is 50 mm of Hg is:}$
Options:
  • 1. $3 \text{ mol}$
  • 2. $0.5 \text{ mol}$
  • 3. $1 \text{ mol}$
  • 4. $2 \text{ mol}$
Solution:
$\text{Hint: Relative lowering in vapor pressure}$ $\text{Step 1:}$ $\text{The reaction is as follows:}$ $\text{K}_2\text{SO}_4 \rightarrow 2\text{K}^+ + \text{SO}_4^{2-}$ $\text{The value of } i = 3$ $\text{Step 2:}$ $\frac{10}{50} = \frac{3n_B}{3n_B + 12}$ $3n_B + 12 = 15n_B$ $12n_B = 12$ $n_B = 1$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}