Import Question JSON

Current Question (ID: 18092)

Question:

$\text{The boiling point of } 0.2 \text{ mol kg}^{-1} \text{ solution of X in water is greater than the equimolal solution of Y in water. The correct statement in this case is:}$

Options:

1. $\text{X is undergoing dissociation in water.}$
2. $\text{Molecular mass of X is greater than the molecular mass of Y.}$
3. $\text{Molecular mass of X is less than the molecular mass of Y.}$
4. $\text{Y is undergoing dissociation in water while X undergoes no change.}$

Solution:

$\text{Hint: } \Delta T_b = K_b m$ $\text{Step 1:}$ $\text{As } \Delta T_b = K_b m \text{ i.e. } \Delta T_b \propto m$ $\text{where } m \text{ is the molality of the solution}$ $K_b \text{ is molal boiling point constant or ebullioscopic constant.}$ $\text{Also, } \Delta T_b = iK_bm \text{ or } \Delta T_b \propto i$ $\text{where, } i \text{ is van't Hoff factor}$ $\text{Step 2:}$ $\text{As } \Delta T_b \text{ of solution X is greater than } \Delta T_b \text{ of solution Y (given) i.e. observed}$ $\text{colligative property is greater than normal colligative property).}$ $\therefore i \text{ of solution X} > i \text{ of solution Y}$ $\text{Or we can say,}$ $\text{Solution X is undergoing dissociation.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}