Import Question JSON

Current Question (ID: 18093)

Question:

$\text{Aluminium phosphate is 100 \% ionized in 0.01 m aqueous solution. Hence, } \frac{\Delta T_b}{K_b} \text{ is-}$

Options:

1. $0.01 \text{ m}$
2. $0.015 \text{ m}$
3. $0.0175 \text{ m}$
4. $0.02 \text{ m}$

Solution:

$\text{HINT: Use the relation between } \Delta T_b \text{ and } K_b$ $\text{Step 1:}$ $\text{For 100 \% dissociated of } \text{AlPO}_4, \text{ the reaction is as follows:}$ $\text{AlPO}_4 \rightarrow \text{Al}^{3+} + \text{PO}_4^{3-}$ $\text{The value of } i \text{ is 2}$ $\text{Step 2:}$ $\text{Calculate the value of } \frac{\Delta T_b}{K_b} \text{ is as follows:}$ $\frac{\Delta T_b}{K_b} = i \times m = 2 \times 0.01 = 0.02$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}