Import Question JSON

Current Question (ID: 18095)

Question:

$\text{The latent heat of vaporization of water is } 540 \text{ cal g}^{-1} \text{ at } 100 \degree \text{C. } K_b \text{ for water is:}$

Options:

1. $0.562 \text{ K m}^{-1}$
2. $1.86 \text{ K m}^{-1}$
3. $0.515 \text{ K m}^{-1}$
4. $5.12 \text{ K m}^{-1}$

Solution:

$\text{Hint: } K_b = \frac{0.002 \times T_B^2}{L_v}$ $\text{Calculate the value of } K_b \text{ as follows:}$ $K_b = \frac{0.002 \times T_B^2}{L_v}$ $= \frac{0.002 \times (373)^2}{540}$ $= 0.515 \text{ K mole}^{-1}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}