Import Question JSON

Current Question (ID: 18096)

Question:

$\text{Select the correct option based on statements below:}$ $\text{Assertion (A):}$ $\text{When methyl alcohol is added to water, boiling point of water increases.}$ $\text{Reason (R):}$ $\text{When a volatile solute is added to a volatile solvent, elevation in boiling point is observed.}$

Options:

1. $\text{Both (A) and (R) are True and (R) is the correct explanation of (A).}$
2. $\text{Both (A) and (R) are True but (R) is not the correct explanation of (A).}$
3. $\text{(A) is True but (R) is False.}$
4. $\text{Both (A) and (R) are False.}$

Solution:

$\text{Hint: Volatile solutes make the solvent to evaporate at a lesser temperature}$ $\text{Methyl alcohol and water both are volatile liquids which when mixed}$ $\text{together to form a binary solution, the vapour pressure of this solution becomes}$ $\text{more as compared to individual pure components. This affects the boiling}$ $\text{point of water with a decrease.}$ $\text{Hence, when methyl alcohol added to the water the boiling point of the water}$ $\text{decreases because easily volatile solutes make the solvent to evaporate at a}$ $\text{lesser temperature when compared to normal solvent.}$ $\text{Hence, both Assertion and Reason is wrong statements.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}