Import Question JSON

Current Question (ID: 18099)

Question:

$\text{The freezing point of depression constant } (K_f) \text{ of benzene is } 5.12 \text{ K kg mol}^{-1}. $ $\text{The freezing point depression for the solution of molality } 0.078 \text{ m containing a non-electrolyte solute in benzene is:} $ $\text{(rounded off up to two decimal places)}$

Options:

1. $0.80 \text{ K}$
2. $0.40 \text{ K}$
3. $0.60 \text{ K}$
4. $0.20 \text{ K}$

Solution:

$\Delta T_f = K_f \times m$ $\text{Step 1:}$ $\text{The given values are as follows:}$ $K_f = 5.12 \text{ K kg mol}^{-1}, \text{ and } m = 0.078 \text{ m}$ $\text{Step 2:}$ $\Delta T_f = K_f \times m$ $= 5.12 \times 0.078$ $= 0.40 \text{ K}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}