Import Question JSON

Current Question (ID: 18101)

Question:

$\text{Freezing point of an aqueous solution is } -0.166^\circ \text{C. Elevation of boiling point of the same solution would be-}$ $\left( K_b = 0.512 \text{ K m}^{-1} \text{ and } K_f = 1.66 \text{ K m}^{-1} \right)$

Options:

1. $0.18^\circ \text{C}$
2. $0.05^\circ \text{C}$
3. $0.09^\circ \text{C}$
4. $0.23^\circ \text{C}$

Solution:

$\text{Use general expression of depression in freezing point and elevation in boiling point.}$ $\text{Step 1:}$ $\text{Freezing point of solution} = -0.166^\circ \text{C}$ $\text{Freezing point's depression} = 0 - (-0.166) = 0.166^\circ \text{C}$ $\text{As, } \Delta T_f = K_f \cdot m$ $0.166 = 1.66 \times m$ $m = 0.1$ $\text{Step 2:}$ $\text{Finding elevation in boiling point-}$ $\Delta T_b = K_b \cdot m$ $= 0.512 \times 0.1$ $= 0.0512^\circ \text{C} \simeq 0.05^\circ \text{C}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}