Import Question JSON

Current Question (ID: 18103)

Question:

$\text{A solution containing } 6.8 \text{ g of a non-ionic solute in } 100 \text{ g of water was found to freeze at } -0.93 ^\circ \text{C.}$ $\text{The freezing point depression constant of water is } 1.86.$ $\text{The molecular weight of the solute is-}$

Options:

1. $13.6 \text{ m}$
2. $34 \text{ m}$
3. $68 \text{ m}$
4. $136 \text{ m}$

Solution:

$\text{Hint: Depression in freezing point}$ $\text{Step 1:}$ $\text{The formula is as follows:}$ $T_f^0 - T_f = k_f \times m$ $M_A = \frac{1000 \times K_f \times W_A}{\Delta T_f \times W_B}$ $\text{Step 2:}$ $M_A = \frac{1000 \times 1.86 \times 6.8}{0.93 \times 100} = 136$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}