Import Question JSON

Current Question (ID: 18110)

Question:

$\text{The incorrect statement among the following is:}$

Options:

1. $\text{Two different solutions of sucrose of the same molality prepared in different solvents will have the same depression in freezing point.}$
2. $\text{The osmotic pressure of a solution is given by the equation } \pi = CRT \text{ (where C is the molarity of the solution)}$
3. $\text{Decreasing order of osmotic pressure for 0.01 M aqueous solutions of BaCl}_2 > \text{KCl} > \text{CH}_3\text{COOH} > \text{sucrose}$
4. $\text{The vapour pressure exerted by a volatile component of a solution is directly proportional to its mole fraction in the solution.}$

Solution:

$\text{Hint: Every solvent has its } K_f \text{ value.}$ $\text{According to the definition of depression in freezing point}$ $\Delta T_f = K_f m$ $\text{where, } K_f = \text{freezing point depression constant, the value of } K_f \text{ depends upon the nature of the solvent.}$ $\text{Although the solution has the same molality, the solvent is different and their } K_f \text{ value is also different.}$ $\text{Thus, two different solutions of sucrose of the same molality prepared in different solvents will have different depression in freezing point.}$ $\text{N.B = for a solution containing non-volatile solute, VP is directly proportional to mole fraction of solvent}$ $\text{and for a solution containing volatile solute, VP is directly proportional to mole fraction of solute or solvent present in the solution}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}