Import Question JSON

Current Question (ID: 18116)

Question:

$\text{Match the items given in Column I and Column II.}$ $\begin{array}{|c|c|} \hline \text{Column I} & \text{Column II} \\ \hline \text{A. Saturated solution} & \text{1. Solution having same osmotic pressure at a given temperature as that of a given solution.} \\ \text{B. Hypertonic solution} & \text{2. A solution whose osmotic pressure is less than that of another.} \\ \text{C. Isotonic solution} & \text{3. A solution that contains the maximum amount of solute that can be dissolved in a given amount of solvent at a given temperature.} \\ \text{D. Hypotonic solution} & \text{4. A solution whose osmotic pressure is more than that of another.} \\ \hline \end{array}$ $\text{Codes:}$ $\begin{array}{cccc} \text{A} & \text{B} & \text{C} & \text{D} \\ 1. & 2 & 3 & 4 & 1 \\ 2. & 2 & 4 & 3 & 1 \\ 3. & 3 & 4 & 1 & 2 \\ 4. & 1 & 2 & 3 & 4 \\ \end{array}$

Options:

1. $1 \ (3\%)$
2. $2 \ (5\%)$
3. $3 \ (92\%)$
4. $4 \ (3\%)$

Solution:

$\text{Hint: Isotonic solutions have the same osmotic pressure.}$ $\text{A. Saturated solution: A solution that contains maximum amounts of solute that can be dissolved in a given amount of solvent at a given temperature.}$ $\text{B. Isotonic solution: A solution having the same osmotic pressure at a given temperature as that of a given solution is known as an isotonic solution.}$ $\text{C. Hypotonic solution: A solution whose osmotic pressure is less than another is known as a hypotonic solution.}$ $\text{D. Hypertonic solution: A solution whose osmotic pressure is greater than another is known as a hypertonic solution.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}