Import Question JSON

Current Question (ID: 18157)

Question:

$\text{Consider the change in the oxidation state of Bromine corresponding to different emf values as shown in the diagram below:}$ $\text{BrO}_4^- \xrightarrow{1.82V} \text{BrO}_3^- \xrightarrow{1.5V} \text{HBrO} \xrightarrow{1.595V} \text{Br}_2 \xrightarrow{1.065V} \text{Br}^- $ $\text{Then the species undergoing disproportionation is:}$

Options:

1. $\text{BrO}_3^-$
2. $\text{BrO}_4^-$
3. $\text{Br}_2$
4. $\text{HBrO}$

Solution:

$\text{HINT: Calculate } E^\circ_{\text{cell}} \text{ corresponding to each compound's undergoing disproportionation reaction.}$ $\text{Explanation:}$ $\text{Only the following combination gives a positive } E^\circ_{\text{cell}} \text{ value.}$ $E^\circ_{\text{cell}} = \text{Standard oxidation potential of anode + standard reduction potential of cathode}$ $= -1.5 + 1.595$ $= 0.095V$ $\text{The positive value of the net cell reaction indicates that the overall cell reaction is spontaneous.}$ $\text{Since } E^\circ_{\text{cell}} \text{ is positive, so, } \Delta G^\circ \text{ will be negative. Hence, HBrO undergoes a disproportionation reaction.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}