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Current Question (ID: 18181)

Question:
$\text{A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH} = 10 \text{ and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of the electrode would be:}$
Options:
  • 1. $0.59 \text{ V}$
  • 2. $0.118 \text{ V}$
  • 3. $1.18 \text{ V}$
  • 4. $0.059 \text{ V}$
Solution:
$\text{E}_{\text{cell}} = 0.0591 \times \text{pH}$ $\text{As } \text{E}_{\text{cell}} = 0.0591 \times \text{pH and for reaction i.e. } \frac{1}{2} \text{H}_2 \rightarrow \text{H}^+ + \text{e}^- $ $\text{Given: pH} = 10$ $\text{On substituting: } \text{E}_{\text{cell}} = 0.0591 \times 10 = 0.591 \text{ V}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}