Import Question JSON

Current Question (ID: 18184)

Question:

$\text{For a cell involving one electron } E^\circ_{\text{cell}} = 0.59 \text{ V at } 298 \text{ K.}$ $\text{The equilibrium constant for the cell reaction is:}$ $\left[ \text{Given that } \frac{2.303 \ RT}{F} = 0.059 \text{ V at } T = 298 \text{K} \right]$

Options:

1. $1.0 \times 10^{30}$
2. $1.0 \times 10^{2}$
3. $1.0 \times 10^{5}$
4. $1.0 \times 10^{10}$

Solution:

$\text{HINT: } E^\circ_{\text{cell}} = \frac{0.0591}{n} \log K$ $\text{Explanation:}$ $\text{STEP 1:}$ $E_{\text{cell}} = E^\circ_{\text{cell}} - \frac{0.0591}{n} \log Q$ $\text{At equilibrium,}$ $E_{\text{cell}} = 0$ $Q = K$ $\text{STEP 2:}$ $\therefore E^\circ_{\text{cell}} = \frac{0.0591}{n} \log K$ $0.59 = 0.059 \log K$ $\log K = \frac{0.590}{0.059}$ $= 10$ $\log K = 10$ $K = \text{antilog } 10$ $= 1.0 \times 10^{10}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}