Import Question JSON

Current Question (ID: 18187)

Question:

$\text{The useful work of the reaction } \text{Ag}(s) + \frac{1}{2}\text{Cl}_2(g) \rightarrow \text{AgCl}(s) \text{ is:}$ $\text{Given,}$ $E^\circ_{\text{Cl}_2/\text{Cl}^-} = +1.36 \text{ V},$ $E^\circ_{\text{AgCl}/\text{Ag},\text{Cl}^-} = 0.22 \text{ V},$ $P_{\text{Cl}_2} = 1 \text{ atm and}$ $T = 298 \text{K}$

Options:

1. $-110 \text{ kJ/mol}$
2. $220 \text{ kJ/mol}$
3. $55 \text{ kJ/mol}$
4. $1000 \text{ kJ/mol}$

Solution:

$\text{HINT: } \Delta G^\circ = -nFE^\circ$ $\text{STEP 1:}$ $(1) \text{AgCl}(s) + e \rightarrow \text{Ag}(s) + \text{Cl}^- \quad E^\circ = 0.22 \text{ V}$ $(2) \frac{1}{2}\text{Cl}_2 + e \rightarrow \text{Cl}^- \quad E^\circ = 1.36 \text{ V}$ $\text{We get,}$ $\text{Ag}(s) + \frac{1}{2}\text{Cl}_2(g) \rightarrow \text{AgCl}(s) \quad E^\circ_{\text{cell}} = 1.14 \text{ V}$ $\text{STEP 2: Useful work is } \Delta G^\circ$ $\therefore \Delta G^\circ = -nFE^\circ = (1)(96500)(1.14) = -110 \text{ kJ/mol}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}