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Current Question (ID: 18196)

Question:

$\text{The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm}^{-1}. \text{ The molar conductivity will be -}$

Options:

1. $124 \text{ S cm}^2 \text{ mol}^{-1}$
2. $134 \text{ S cm}^2 \text{ mol}^{-1}$
3. $128 \text{ S cm}^2 \text{ mol}^{-1}$
4. $136 \text{ S cm}^2 \text{ mol}^{-1}$

Solution:

$\text{HINT: } \Lambda_m = \frac{k \times 1000}{c}$ $\text{Step 1:}$ $\text{Given values are:}$ $k = 0.0248 \text{ S cm}^{-1}, \text{ concentration } (c) = 0.20 \text{ M}$ $\text{Step 2:}$ $\text{Calculate the molar conductivity as follows:}$ $\therefore \text{ Molar conductivity, } \Lambda_m = \frac{k \times 1000}{c}$ $= \frac{0.0248 \times 1000}{0.2}$ $= 124 \text{ S cm}^2 \text{ mol}^{-1}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}