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Current Question (ID: 18206)

Question:
$\text{(c) The unit of molar conductivity is S cm}^2 \text{ mol}^{-1}$ $\text{(d) Molar conductivity increases with an increase in concentration.}$
Options:
  • 1. (a)
  • 2. (a) \text{ and } (d)
  • 3. (b) \text{ and } (d)
  • 4. (a) \text{ and } (c)
Solution:
$\text{HINT: Molar conductivity is inversely proportional to the concentration.}$ $\text{Explanation:}$ $\text{The first statement is wrong. The unit of conductivity is S cm}^{-1}. \text{The second and third statements are the correct statements.}$ $\text{The fourth statement is the incorrect statement. The molar conductivity is inversely proportional to the concentration. Hence, molar conductivity increases with decreases in concentration.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}