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Current Question (ID: 18211)

Question:
$\text{The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 } \Omega. \text{ The cell constant if conductivity of 0.001 M KCl solution at 298 K is } 0.146 \times 10^{-3} \text{ S cm}^{-1} \text{ will be:}$
Options:
  • 1. $0.32 \text{ cm}^{-1}$
  • 2. $0.47 \text{ cm}$
  • 3. $0.22 \text{ cm}^{-1}$
  • 4. $0.23 \text{ cm}$
Solution:
$\text{Cell constant} = \text{Resistance} \times \text{Conductivity}$ $\text{Conductivity (k)} = 0.146 \times 10^{-3} \text{ S cm}^{-1}$ $\text{Resistance (R)} = 1500 \text{ ohm}$ $\text{Cell constant} = k \times R$ $= 0.146 \times 10^{-3} \text{ S cm}^{-1} \times 1500 \text{ ohm}$ $= 0.22 \text{ cm}^{-1}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}