Import Question JSON

Current Question (ID: 18227)

Question:

$\text{In producing chlorine through electrolysis, 100 W power at 125 V is being consumed.}$ $\text{The liberation of chlorine per min is:}$ $\text{(ECE of chlorine is } 0.367 \times 10^{-6} \text{ kg/C)}$

Options:

1. $17.6 \text{ mg}$
2. $21.3 \text{ mg}$
3. $24.3 \text{ mg}$
4. $13.6 \text{ mg}$

Solution:

$\text{HINT: Faraday's law of electrolysis.}$ $\text{STEP 1:}$ $\text{Power consumed in electrolysis, } P = 100 \text{ W}$ $\text{Voltage applied, } V = 125 \text{ V}$ $\text{So, current in the solution,}$ $i = \frac{P}{V} = \frac{100}{125} = 0.8 \text{ A}$ $\text{STEP 2:}$ $\text{According to the first law of Faraday, } m \propto Q \Rightarrow m = zQ$ $\text{where } z \text{ is a constant called 'electrochemical equivalent' (ECE)}$ $\text{Also, } Q = it$ $\therefore m = zit$ $\text{STEP 3:}$ $\text{Given,}$ $z = 0.367 \times 10^{-6} \text{ kg/C}, i = 0.8 \text{ A}, t = 60 \text{ s}$ $\text{Hence, } m = 0.367 \times 10^{-6} \times 0.8 \times 60$ $= 17.6 \times 10^{-6} \text{ kg}$ $= 17.6 \text{ mg}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}