Import Question JSON

Current Question (ID: 18246)

Question:

$\text{The correct statement about the given galvanic cell equation is -}$ $\text{Zn}_{(s)} + 2\text{Ag}^+_{(aq)} \rightarrow \text{Zn}^{2+}_{(aq)} + 2\text{Ag}_{(s)}$

Options:

1. $\text{The current will flow from silver to zinc in the external circuit.}$
2. $\text{The current will flow from zinc to silver in the external circuit.}$
3. $\text{The current will flow from silver to zinc in the internal circuit.}$
4. $\text{The current will flow from zinc to silver in the internal circuit.}$

Solution:

$\text{HINT: Current flow from cathode to anode in a galvanic cell.}$ $\text{Explanation:}$ $\text{The galvanic cell in which the given reaction takes place is depicted as:}$ $\text{Zn}_{(s)} \vert \text{Zn}^{2+}_{(aq)} \Vert \text{Ag}^+_{(aq)} \vert \text{Ag}_{(s)}$ $(i) \text{Zn electrode (anode) is negatively charged.}$ $(ii) \text{Ions are carriers of current in the cell and in the external circuit, current will flow from silver to zinc.}$ $(iii) \text{The reaction taking place at the anode is given by,}$ $\text{Zn}_{(s)} \rightarrow \text{Zn}^{2+}_{(aq)} + 2e^- $ $\text{The reaction taking place at the cathode is given by,}$ $\text{Ag}^+_{(aq)} + e^- \rightarrow \text{Ag}_{(s)}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}