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Current Question (ID: 18250)

Question:
$\text{When a copper wire is immersed in a solution of } \text{AgNO}_3, \text{ the colour of the solution becomes blue because copper:}$ $1. \text{ Forms a soluble complex with } \text{AgNO}_3$ $2. \text{ Is oxidised to } \text{Cu}^{2+}$ $3. \text{ Is reduced to } \text{Cu}^{2-}$ $4. \text{ Splits up into atomic form and dissolves}$
Options:
  • 1. $\text{Forms a soluble complex with } \text{AgNO}_3$
  • 2. $\text{Is oxidised to } \text{Cu}^{2+}$
  • 3. $\text{Is reduced to } \text{Cu}^{2-}$
  • 4. $\text{Splits up into atomic form and dissolves}$
Solution:
$\text{Cu is above Ag in electrochemical series and thus,}$ $\text{Cu} + 2 \text{Ag}^+ \rightarrow \text{Cu}^{2+} + 2 \text{Ag} \text{ reaction occurs.}$ $\text{i.e Cu gets oxidised to } \text{Cu}^{2+}.$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}