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Current Question (ID: 18252)

Question:

$\text{A hypothetical electrochemical cell is shown below.}$ $\text{A|A}^{+}(x\ \text{M})\ ||\ \text{B}^{+}(y\ \text{M})|\text{B}}$ $\text{The Emf measured is } +0.20\ \text{V. The cell reaction is:}$

Options:

1. $\text{A}^{+} + \text{B} \rightarrow \text{A} + \text{B}^{+}$
2. $\text{A}^{+} + \text{e}^{-} \rightarrow \text{A} ; \text{B}^{+} + \text{e}^{-} \rightarrow \text{B}$
3. $\text{The cell reaction cannot be predicted.}$
4. $\text{A} + \text{B}^{+} \rightarrow \text{A}^{+} + \text{B}$

Solution:

$\text{HINT: See the cell representation.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{Electrochemical cell}$ $\text{A|A}^{+}(x\ \text{M})\ ||\ \text{B}^{+}(y\ \text{M})|\text{B}}$ $\text{Since given EMF of cell is positive, hence the cell reaction is feasible.}$ $\text{STEP 2:}$ $\text{The half cell reactions can be written as:}$ $(i)\ \text{At anode or negative pole:}$ $\text{A} \rightarrow \text{A}^{+} + \text{e}^{-} \ (\text{oxidation})$ $(ii)\ \text{At cathode or positive pole:}$ $\text{B}^{+} + \text{e}^{-} \rightarrow \text{B} \ (\text{reduction})$ $\text{Hence, cell reaction is obtained by adding both equations as}$ $\text{A} + \text{B}^{+} \rightarrow \text{A}^{+} + \text{B}, \ E^{\circ}_{\text{cell}} = +0.20\ \text{V}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}