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Current Question (ID: 18261)

Question:
$\text{When a lead storage battery is discharged, then:}$ $1. \ \text{SO}_2 \ \text{is evolved.}$ $2. \ \text{Lead is formed.}$ $3. \ \text{Lead sulphate is consumed.}$ $4. \ \text{Sulphuric acid is consumed.}$
Options:
  • 1. $\text{SO}_2 \ \text{is evolved.}$
  • 2. $\text{Lead is formed.}$
  • 3. $\text{Lead sulphate is consumed.}$
  • 4. $\text{Sulphuric acid is consumed.}$
Solution:
$\text{HINT: Sulphuric acid is consumed during discharging.}$ $\text{Explanation:}$ $\text{The reactions occurring during the operation of the battery are:}$ $\text{Anode: Pb(s) + \text{HSO}_4^- + \text{H}_2\text{O} \rightarrow \text{PbSO}_4(\text{s}) + 2e^- + \text{H}_3\text{O}^+;}$ $E^\circ_{\text{OP}} = +0.356 \text{ V}$ $\text{Cathode: PbO}_2 + \text{HSO}_4^- + 3\text{H}_3\text{O}^+ + 2e^- \rightarrow \text{PbSO}_4(\text{s}) + 5\text{H}_2\text{O};}$ $E^\circ_{\text{RP}} = +1.685 \text{ V}$ $\text{Net change: Pb(s) + 2\text{HSO}_4^- + 2\text{H}_3\text{O}^+ + \text{PbO}_2(\text{s})} \rightarrow 2\text{PbSO}_4(\text{s}) + E^\circ = 2.041 \text{ V}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}