Import Question JSON

Current Question (ID: 18314)

Question:

$\text{The correct statement based on the graph below is:}$ $\text{Activated complex}$ $\text{Energy}$ $E_1$ $\text{Products}$ $E_2$ $\text{Reactants}$ $\text{Reaction coordinate}$

Options:

1. $\text{The activation energy of the forward reaction is } E_1 + E_2 \text{ and the product is less stable than reactant.}$
2. $\text{The activation energy of the forward reaction is } E_1 + E_2 \text{ and the product is more stable than the reactant.}$
3. $\text{The activation energy of both forward and backward reaction is } E_1 + E_2 \text{ and reactant is more stable than the product.}$
4. $\text{The activation energy of the backward reaction is } E_1 \text{ and the product is more stable than reactant.}$

Solution:

$\text{Activation energy is the minimum energy required to convert reactant molecules to product molecules.}$ $\text{Here, the energy gap between reactants and activated complex is the sum of } E_1 \text{ and } E_2.$ $\text{Activation energy } = E_1 + E_2$ $\text{The product is less stable than the reactant as the energy of the product is greater than the reactant.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}