Import Question JSON

Current Question (ID: 18335)

Question:

$\text{The half-life period for a first-order reaction is 20 minutes. The time required to change the concentration of the reactants from 0.08 M to 0.01 M will be:}$

Options:

1. $20 \text{ minutes}$
2. $60 \text{ minutes}$
3. $40 \text{ minutes}$
4. $50 \text{ minutes}$

Solution:

$\text{HINT: Use general expression of first order kinetics.}$ $K = \frac{2.303}{t} \log \frac{a}{a-x}$ $\frac{0.6932}{20} = \frac{2.303}{t} \log \frac{0.08}{0.01}$ $= \frac{2.303}{t} \log 8 = \frac{2.303 \times 3 \times \log 2}{t}; \frac{1}{20} = \frac{3}{t}$ $t = 60 \text{ minutes}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}