Import Question JSON

Current Question (ID: 18347)

Question:

$\text{A first-order reaction is 50 \% completed in } 1.26 \times 10^{14} \text{ s. The time required for 100 \% completion of the reaction will be:}$

Options:

1. $1.26 \times 10^{15} \text{ s}$
2. $2.52 \times 10^{14} \text{ s}$
3. $2.52 \times 10^{28} \text{ s}$
4. $\text{Infinite}$

Solution:

$\text{HINT: } k = \frac{1}{t} \ln \left[ \frac{A_0}{A_t} \right]$ $\text{Explanation:}$ $\text{The time taken for half the reaction to complete, i.e., the time in which the concentration of a reactant is reduced to half of its original value is called half-life period of the reaction.}$ $\text{But it is impossible to perform 100\% of the reaction. Whole of the substance never reacts because in every half-life, 50\% of the substance reacts. Hence, time taken for 100\% completion of a reaction is infinite.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}