Import Question JSON

Current Question (ID: 18351)

Question:
$\text{If in the fermentation of sugar in an enzymatic solution that is } 0.12 \text{ M, the concentration of the sugar is reduced to } 0.06 \text{ M in } 10 \text{ h and to } 0.03 \text{ M in } 20 \text{ h, the order of the reaction will be:}$
Options:
  • 1. $1$
  • 2. $2$
  • 3. $3$
  • 4. $0$
Solution:
$\text{Given, concentration is reduced from } 0.12 \text{ M to } 0.06 \text{ M in } 10 \text{ h}$ $\text{So, } t_{1/2} = 10 \text{ h}$ $\text{Conc reduced from } 0.12 \text{ M to } 0.03 \text{ M in } 20 \text{ hr.}$ $\text{So, } t_{3/4} = 20 \text{ h}$ $t_{3/4} = 2 \times t_{1/2}$ $\text{This is valid only for 1st Order Reaction.}$ $\text{So, Order is } 1$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}