Import Question JSON

Current Question (ID: 18394)

Question:
$\text{The probable reasons of the exothermic nature of adsorption is:}$
Options:
  • 1. $\text{Adsorption leads to a decrease in the residual forces on the surface of the adsorbent.}$
  • 2. $\Delta S \text{ is negative.}$
  • 3. $\text{Both (1) and (2)}$
  • 4. $\text{None of the above.}$
Solution:
$\text{Bond formation is always exothermic in nature.}$ $\text{This statement can be explained in two ways.}$ $\text{(i) Adsorption leads to a decrease in the residual forces on the surface of the adsorbent.}$ $\text{This causes a decrease in the surface energy of the adsorbent. Therefore, adsorption is always exothermic.}$ $\text{(ii) } \Delta H \text{ of adsorption is always negative. When a gas is adsorbed on a solid surface, its movement is restricted leading to a decrease in the entropy of the gas i.e., } \Delta S \text{ is negative.}$ $\text{Now for a process to be spontaneous, } \Delta G \text{ should be negative.}$ $\therefore \Delta G = \Delta H - T \Delta S$ $\text{Since } \Delta S \text{ is negative, } \Delta H \text{ has to be negative to make } \Delta G \text{ negative. Hence, adsorption is always exothermic.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}