Import Question JSON

Current Question (ID: 18406)

Question:

$\text{The equation that represents a Freundlich adsorption isotherm is:}$

Options:

1. $\frac{x}{m} = kp^{0.3}$
2. $\frac{x}{m} = kp^{2.5}$
3. $\frac{x}{m} = kp^{-0.5}$
4. $\frac{x}{m} = kp^{-1}$

Solution:

$\text{HINT: } \frac{x}{m} = kp^{1/n}$ $\text{Freundlich adsorption isotherm is represented as } \frac{x}{m} = kp^{1/n}$ $\text{At high pressure } \frac{1}{n} = 0$ $\Rightarrow \frac{x}{m} \propto P^0$ $\text{At low pressure } \frac{1}{n} = 1$ $\Rightarrow \frac{x}{m} \propto P$ $\text{so } n \text{ should be higher than 1 and } +ve$ $\text{Freundlich adsorption isotherm fails at higher pressure.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}