Import Question JSON

Current Question (ID: 18412)

Question:

$\text{Colloids can be classified on the basis of:}$

Options:

1. $\text{Physical states of components.}$
2. $\text{Nature of dispersed phase.}$
3. $\text{Interaction between the dispersed phase and dispersion medium.}$
4. $\text{All of the above.}$

Solution:

$\text{HINT: A colloid is a mixture in which one substance of microscopically dispersed insoluble particles are suspended throughout another substance.}$ $\text{Explanation:}$ $\text{(1) On the basis of the physical state of the components (by components we mean the dispersed phase and dispersion medium). Depending on whether the components are solids, liquids, or gases, we can have eight types of colloids.}$ $\text{(2) On the basis of the dispersion medium, sols can be divided as:}$ $\begin{array}{|c|c|} \hline \text{Dispersion Medium} & \text{Name of sol} \\ \hline \text{Water} & \text{Aquasol or hydrosol} \\ \text{Alcohol} & \text{Alcosol} \\ \text{Benzene} & \text{Benzosol} \\ \text{Gases} & \text{Aerosol} \\ \hline \end{array}$ $\text{(3) On the basis of the nature of the interaction between the dispersed phase and dispersion medium, the colloids can be classified as lyophilic (solvent attracting) and lyophobic (solvent repelling).}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}