Import Question JSON

Current Question (ID: 18418)

Question:
$\text{The coagulation values in millimoles per litre of the electrolytes used for the coagulation of } \text{As}_2\text{S}_3 \text{ are given below}$ $\text{I. (NaCl) = 52, II. (BeCl}_2\text{) = 0.69, III. (MgSO}_4\text{) = 0.22}$ $\text{What is the correct order of their coagulating power?}$
Options:
  • 1. $\text{I > II > III}$
  • 2. $\text{II > I > III}$
  • 3. $\text{III > II > I}$
  • 4. $\text{III > I > II}$
Solution:
$\text{The lower the coagulating power, the higher is the coagulation value in millimoles per liter, i.e. coagulating power is inversely proportional to coagulation values.}$ $\text{Thus, the correct order of coagulating power is}$ $\text{MgSO}_4 > \text{BeCl}_2 > \text{NaCl or III > II > I}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}